(5^2-5)/(4^2+8-7x2)

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Solution for (5^2-5)/(4^2+8-7x2) equation: 


D( x )

4^2-(7*x^2)+8 = 0

4^2-(7*x^2)+8 = 0

4^2-(7*x^2)+8 = 0

4^2-7*x^2+8 = 0

-7*x^2 = -24 // : -7

x^2 = 24/7

x^2 = 24/7 // ^ 1/2

abs(x) = (24/7)^(1/2)

x = (24/7)^(1/2) or x = -(24/7)^(1/2)

x in (-oo:-(24/7)^(1/2)) U (-(24/7)^(1/2):(24/7)^(1/2)) U ((24/7)^(1/2):+oo)

(5^2-5)/(4^2-(7*x^2)+8) = 0

(5^2-5)/(4^2-7*x^2+8) = 0

20/(24-7*x^2) = 0

x belongs to the empty set

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